Equipment: DC powe supply, circuit board (fuse, switch, three bulbs), multimeter, wires.
Measured the available voltage, voltage drop and current flow at different parts of the compound circuit.
Calculated watts used at each parallel light bulb using V(voltage available at paralleled bulbs) x I(current through paralleled bulbs), and watts used at series bulb using V(voltage available at series bulb) x I(current through series bulb).
I can see all three bulbs brighter than put them in series, but not that bright than put them in parallel circuit.
The series bulb makes other two bulbs less bright than before, because the bulb in series shared some of the voltage from the supplier.
The amperage in the compound circuit is the same as the series part of the circuit, and equals the sum of the current in all paralleled part of the circuit.
The total voltage alailable in the compound circuit is the same as the sum of voltage avaiable at the series part of circuit and voltage available at the parallel part of circuit. And the voltage available for each paralleled components are the same.