Equipment: DC powe supply, circuit board (fuse, switch, two bulbs), multimeter, wires.
From the data that I measured, I found the voltage available at the battery is the same as the total voltage drop of different components.
Measured amps in the circuit.
From the data that I measured, I found Amps in this circuit less that the individual circuit, because the resistance in this circuit is larger than the single bulb circuit.
Then calculated the total resistance using V(available at the battery) / I, and the watts used by each light bulb using V(voltage drop at bulb one/two) x I.
From the watts that I calculated, I can found both lights will look not that bright than before, because two bulbs were using the supply voltage together.
THREE BULBS
Equipment: DC powe supply, circuit board (fuse, switch, three bulbs), multimeter, wires.
From the data that I measured, I found the voltage drop across the bulb is smaller than two bulb circuit, because three bulbs shares the voltage available at supply.
By measure the amps in the circuit, I found the amperage less than two bulbs circuit, because they were sharing the voltage together, and there is more resistance than before.
Use V(available at the supply) / I, I can calculate the total resistance in the circuit; and calculate the watts used by each bulb using V(voltage drop of each bulb) x I.
In this three bulbs series circuit, all of the bulbs look not that bright than two bulbs circuit. The total voltage drop of each components in the sercies circuits equals the voltage available at the supplier.
